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When does the norm of a Fourier multiplier dominate its L∞ norm?

Research output: Contribution to journalArticle

Alexei Karlovich, Eugene Shargorodsky

Original languageEnglish
Pages (from-to)901-941
Number of pages41
JournalPROCEEDINGS OF THE LONDON MATHEMATICAL SOCIETY
Volume118
Issue number4
Early online date10 Oct 2018
DOIs
Accepted/In press23 Sep 2018
E-pub ahead of print10 Oct 2018
PublishedApr 2019

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Abstract

One can define Fourier multipliers on a Banach function space using the direct and inverse Fourier transforms on L 2 (R n ) or using the direct Fourier transform on SR n and the inverse one on S'R n . In the former case, one assumes that the Fourier multipliers belong to L∞R n , while in the latter one this requirement may or may not be included in the definition. We provide sufficient conditions for those definitions to coincide as well as examples when they differ. In particular, we prove that if a Banach function space XR n satisfies a certain weak doubling property, then the space of all Fourier multipliers MXR n is continuously embedded into L∞R n with the best possible embedding constant one. For weighted Lebesgue spaces L p (R n , w), the weak doubling property is much weaker than the requirement that w is a Muckenhoupt weight, and our result implies that (Formula presented.) for such weights. This inequality extends the inequality for n = 1 from Theorem of [Berkson and Gillespie, Bull. Sci. Math. 122 (1998) 427–454], where it is attributed to J. Bourgain. We show that although the weak doubling property is not necessary, it is quite sharp. It allows the weight w in L p (R n , w) to grow at any subexponential rate. On the other hand, the space L p (R, e x ) has plenty of unbounded Fourier multipliers.

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